Question

Potassium chlorate(s) can be decomposed to O2(g) and potassium chloride(s) by heating. Calculate the mass of potassium chlorate that must react to produce 187.1 mL of dry O2, measured at STP.

Answer #1

The balanced equation is

2 KClO_{3} ----> 2 KCl + 3 O_{2}

The volume of potassium chlorate = 187.1 mL = 0.1871 L

At STP,

22.4 L of O2 = 1 mole so

0.1871 L of O2 = 0.00835 mole of O2

Therefore, the number of moles of O2 = 0.00835

From the balanced equation we can say that

3 mole of O2 is produced by 2 mole of KClO3 so

0.00835 mole of O2 will be produced by

= 0.00835 mole of O2 *(2 mole of KClO3 / 3 mole of O2)

= 0.005567 mole of KClO3

mass of 1 mole of KClO3 = 122.5495 g

the mass of 0.005567 mole of KClO3 = 0.682 g

Therefore, the mass of potassium chlorate reacts would be 0.682 g

A sample of soilid potassium chlorate was heated and decomposed
into solid potassium chloride and oxygen gas. The oxygen produced
was collected over water at 22 degrees celcius at a total pressure
of 745 Torr. the volume of the gas collected was 0.650 L, and the
vapor pressure of water at 22 degrees celcius is 21 torr.
2 KClO3(s)=2KCl(s)+3O2(g)
First calculate the partial pressre of oxygen in the gas
collected and determine the mass of potassium chlorate in the
sample...

How many grams of potassium chlorate decompose to potassium
chloride and 719 mL of O2 at 128°C and 685 torr?
2 KClO3(s) → 2 KCl(s) + 3 O2 (g)
*please explain

Small quantities of oxygen can be prepared in the laboratory by
heating potassium chlorate, KClO3(s). The equation for the reaction
is
2KclO3 ----> 2KCl+3O2
calculate how many grams of O2(g) can be produced from heating
26.3 grams of KClO3 (S)

When potassium chlorate is heated, potassium chloride and oxygen
gas are formed. The percent yield of the reaction is 83.2%. How
much potassium chlorate must be decomposed to produce 198.5 grams
of oxygen?

How many grams of potassium chlorate decompose to form potassium
chloride and 415 mL O2 at 128°C and 686 torr?
g

Potassium chlorate (KClO3 molar mass 122.5 g/mol) decomposes
into oxygen gas and potassium chloride. When 3.25 grams of
potassium chlorate decomposes at 610 torr and 34*C, what is the
volume of oxygen gas produced? Remember to convert torr to atm and
Celcius to Kelvin. 2 KClO3 --> 3 O2(g) + 2 KCl (s).

How many grams of potassium chlorate decompose to form potassium
chloride and 650. mL O2 at 128°C and 663 torr?

If a 0.500-g sample of a potassium nitrate mixture is decomposed
by heating, what is the milliliter volume of oxygen gas released at
STP?

Small quantities of oxygen gas can be
generated in the laboratory by heating potassium chlorate according
to the reaction below. If 4.74 g of potassium chlorate is heated,
what theoretical mass of oxygen gas should be produced?
2KClO3(s) +
2KCl(s) à 3O2(g)

At elevated temperatures, solid sodium chlorate NaClO3decomposes
to produce sodium chloride, NaCl, and O2 gas. A 0.9560 g sample of
impure sodium chlorate was heated until the production of oxygen
ceased. The oxygen gas was collected over water and occupied a
volume of 63.6 mL at 23.0 ∘C and 737 Torr .
Calculate the mass percentage of NaClO3 in the original sample.
Assume that none of the impurities produce oxygen on heating. The
vapor pressure of water is 21.07 Torr...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 10 minutes ago

asked 12 minutes ago

asked 12 minutes ago

asked 18 minutes ago

asked 19 minutes ago

asked 30 minutes ago

asked 36 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago