Question

When the following reaction is balanced in ACIDIC solution, what is the coefficient for S2O32-? Cr2O7-2...

When the following reaction is balanced in ACIDIC solution, what is the coefficient for S2O32-?

Cr2O7-2 + S2O32- Cr3+ + S4O62-

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Homework Answers

Answer #1

Reduction half reaction

Cr2O7^-2 + 6e^- + 14 H^+ ----> Cr^3+ (aq) + 7 H2O -------(1)

oxidation half reaction

2S2O3^2- --> S4O6^2- + 2e- ---------(2)

equation (2) x 3

6S2O3^2- --> 3 S4O6^2- + 6e- ---------(3)

Add equation (1) + (3)

Cr2O7^-2 + 6e^- + 14 H^+ ----> Cr^3+ (aq) + 7 H2O -------(1)

6S2O3^2- --> 3 S4O6^2- + 6e- ---------(3)

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Cr2O7-2 (aq) + 14 H+ (aq) + 6 S2O32- (aq) --------> 2 Cr3+ (aq) + 3 S4O62- (aq) + 7 H2O (l)

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Coefficient of S2O32- (aq) = 6

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