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If 20 mL of 0.10 M NaOH is added to 40 mL of 0.20 M HC2H3O2,...

If 20 mL of 0.10 M NaOH is added to 40 mL of 0.20 M HC2H3O2, what is the pH of the resulting solution at 25°C? Ka for HC2H3O2 is 1.8 × 10–5 at 25°C.

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Answer #1

millimoles of NaOH = 20 x 0.1 = 2

millimoles of CH3COOH = 40 x 0.2 = 8

CH3COOH   + NaOH -------------------> CH3COONa + H2O

8                      2                                          0                --------------> initial

6                      0                                          2 ----------------> after reaction

pH = pKa + log [CH3COONa / CH3COOH]

pH = 4.74 + log (2/6)

pH = 4.26

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