Question

Consider the complete reaction of 30.5 g of chlorine with oxygen. 2 Cl_2 +7 O_2 --> 2 Cl_2O_7 a). How many grams of oxygen are required? b). how many grams of dichloride heptoxide (182.90 g/mol) would be produced?

Answer 1

2 Cl_2 +7 O_2 --> 2 Cl_2O_7

2Cl2    +    7O2 ------------> 2Cl2O7

2 moles      7 moles

2 moles of Cl2 react with 7 moles of O2

2*71g of Cl2 react with 7*32g of O2

30.5 g of Cl2 react with = 7*32*30.5/2*71   = 48.1g of O2

2Cl2    +    7O2 ------------> 2Cl2O7

2 moles of Cl2 react with O2 to gives 2 moles of Cl2O7

2*71g of Cl2 react with O2 to gives 2*182.9g of Cl2O7

30.5 g of Cl2 react with O2 to gives = 2*182.9*30.5/2*71   = 78.6g of Cl2O7