For any enzyme that follows simple Michaelis-Menten kinetics, when the initial velocity of the reaction is 1/5 of Vmax what is the Substrate concentration?
A) KM << [S]
B) KM = 1/5[S]
C) KM = 4[S]
D) KM = 5[S]
E) KM = [S]
Correct option: A) KM << [S]
V0 = Vmax ([S]/([S] + KM))
if initial concentration V0 = Vmax /5 then
KM = -1.25[S]
This represents KM << [S], this can be also obtained from Lineweaver-Burke plot.
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