Question

In the coordination compound [Cr(NH3)(en)2Cl]Br2, the coordination number (C.N.) and oxidation number (O.N.) of the metal...

In the coordination compound [Cr(NH3)(en)2Cl]Br2, the coordination number (C.N.) and oxidation number (O.N.) of the metal atom are...?

Can you please walk through step by step, I don't understand how to find the coordination number at all!

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Answer #1

[Cr(NH3)(en)2Cl]Br2

outside 2 Br present means +2 charge present on complex

[Cr(NH3)(en)2Cl]+2

NH3 and en are neutral ligands so we take 0 for oxidation state calculation.

Cl is negetive ligand so we consider -1 in oxidation state calculation.

now assume X for Cr oxidation state.

X + 0 + 0 + (-1) = +2

X = +3

oxidation state of Cr = +3

NH3 is monodentate ligand

en is bidentate ligand

Cl also unidentate ligand

total 1 + 2 + 1 = 4

coordination number = 4

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