Question

Use the values of ∆Hof given below to calculate ∆Horxn for the following reaction: C2H5OH (l)+...

Use the values of ∆Hof given below to calculate ∆Horxn for the following reaction:

C2H5OH (l)+ 3O2(g) → 2CO2(g) + 3H2O(g)

Given: ∆Hof (kJ/mol)
C2H5OH (l) -278
O2(g) 0
CO2(g) -394
H2O(g) -242



Use kJ for your answer. ΔHorxn =

Homework Answers

Answer #1

we have:

Hof(C2H5OH) = -278.0 KJ/mol

Hof(O2) = 0.0 KJ/mol

Hof(CO2) = -394.0 KJ/mol

Hof(H2O) = -242.0 KJ/mol

we have the Balanced chemical equation as:

C2H5OH + 3 O2 ---> 2 CO2 + 3 H2O

deltaHo rxn = 2*Hof(CO2) + 3*Hof(H2O) - 1*Hof( C2H5OH) - 3*Hof(O2)

deltaHo rxn = 2*(-394.0) + 3*(-242.0) - 1*(-278.0) - 3*(0.0)

deltaHo rxn = -1236 KJ

Answer: -1236 KJ

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