Question

Calculate the cell potential for the cell below at 25C Ti(s)| Ti(NO3)2(aq) (0.92 M)|| HgCl2(aq) (0.43...

Calculate the cell potential for the cell below at 25C Ti(s)| Ti(NO3)2(aq) (0.92 M)|| HgCl2(aq) (0.43 M)|Hg(l)|

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Answer #1

Nernest equation,

Ti2+ + 2 e− --> Ti(s)    E0 = −1.63 v

Hg2+ + 2 e− ---> Hg(l) E0 = +0.85 v

E0cell = E0cathode - E0anode

         = 0.85- (-1.63)

         = 2.48 v

Cell reaction : Ti(s) +Hg2+(aq) ----> Ti2+(aq) + Hg(l)

   Ecell = E0cell - 0.0591/nlog[[Ti2+]/[Hg2+]]

         = 2.48-(0.0591/2)log(0.92/0.43)

        = 2.47

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