Question

Calculate the theoretical yield, actual yield, and % yield of the Diels-Alder product.

Amount maleic anhydride used: 0.098g

Amount 3-sulfolene used: 0.261g

Diels-alder adduct (MW= 152.15 g) amount recovered: 0.063g

Melting point: 103C

Molar mass maleic anhydride: 98.06 g/mol

Molar mass 3-sulfolene: 118.15 g/mol

Answer 1

Actual yield = 0.063g

Theoretical yield = 0.15206g

% yield = 41.43℅

Explanation

maleic anhydride + 3-sulfolene ---------> Diels alder aduct

this reaction is 1:1 reaction

stoichiometrically, 98.06g of maleic anhydride react with 118.15g of sulfolene

Therefore,

0.098g of maleic anhydride should react with (118.15/98.06)×0.098g = 0.11807g of 3-sulfolene , but actual 3-sulfolene is 0.261g

So, maleic anhydride is limiting reagent

stoichiometrically, 98.06g of maleic anhydride giving 152.15g of Diels - Alder adduct

So, 0.098g of maleic anhydride should give (152.15/98.06)×0.098 = 0.15206g

Theoretical yield = 0.15206g

Actual yield = 0.063g

% yield = (Actual yield/theoretical yield)×100

= (0.063g/0.15206g)×100

= 41.43%