Question

Two substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of substance A is 6.07 g and its initial temperature is 20.8 ∘ C . The mass of substance B is 25.0 g and its initial temperature is 52.3 ∘ C . The final temperature of both substances at thermal equilibrium is 46.6 ∘ C . If the specific heat capacity of substance B is 1.17 J/g ⋅ ∘ C , what is the specific heat capacity of substance A?

Answer 1

A and B areat thermal equilibrium.

Thus the final temperature is same for both.and let that be TK

The heat given by hot metal B = -heat absorbed by other metal A

Heat given by metal B = mass of B x specific heat of B x delta T

= 25.0g x 1.17J/g.K x (46.6-52.3)

=-166.75 J

heat absorbed by metal A = mass of A x specific heat of A x delta T

= 6.07g x specific heat x (46.6 -20.8)

=156.606 xspecific heat

equating

-166.75 J = -156.6 x specific heat

Ths specific heat of A = 1.06 J/g.C