Consider the following reaction: 2 A + 5 B → 3 C + 4 D Under a set of conditions, the average rate of reaction is 0.0256 M/s. What is the rate change with respect to B?
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This question is based on the rate of a reaction with respect to reactants.
The rate of this reaction k can be given as,
K= -∆[A]/2∆t = -∆[B]/5∆t = ∆[C]/3∆t = ∆[D]/4∆t where the number of moles of the compounds are in the denominator.
Hence, with respect to B, the rate is 5k = 5*0.0256
= 0.128 M/s
The rate of the reaction maximally depends on the number of moles of a particular compound in the reaction mixture. More the quantity of a compound, more does it affect the rate.
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