Question

A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.16 V...

A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.16 V at 25 ∘C.

Part A

What is the ratio of the Sn2+ concentrations in the two half-cells?

Express your answer using two significant figures.
[Sn2+(ox)][Sn2+(red) =
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Homework Answers

Answer #1

Sn/Sn+2 ;

Two half reactions;

anode:(OX)           Sn        -----> Sn+2 + 2 e-
Cathode:(Red)     Sn+2 + 2 e- ----> Sn
-------------------------------------
Total reaction: Sn + Sn+2 -----> Sn+2 + Sn


ECell = EoCell - 0.0592/n log[Sn+2(ox)]/[Sn+2(red)]

0.16 V = 0 V - 0.0592/2 log[Sn+2(ox)]/[Sn+2(red)]
-5.40 = log [Sn+2(ox)]/[Sn+2(red)]
[Sn+2(ox)]/[Sn+2(red)] = 3.98 x 10-6
[Sn+2(ox)]/[Sn+2(red)] = 4.0 x 10-6 (two significant figs)

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