Question

Determine the concentration of the ion indicated in each solution.

Part A

K+] in 0.211 M KNO3.

Part B

[NO−3] in 0.185 M Ca(NO3)2

Part C

[Al3+] in 6.8×10⁻² M Al2(SO4)3

Part D

[Na+] in 0.190 M Na3PO4

Answer 1

Part A

K+ in 0.211 M KNO3.

KNO3 ------>K++ NO3-

hence 1M of KNO3 correspond to 1M K+

0.211 M KNO3 correspond to 0.211 M K+

Part B

Ca(NO3)2------>Ca+2+2NO3-

1M of Ca(NO3)2 correspond to 2M NO3-

0.185M Ca(NO3)2 corresond to 2*0.185=0.37M NO3-

Part C

Al2(SO4)3 ---------->2Al+3+ 3SO4-2

1 M Al2(SO4)3 correspond to 2 M Al+3 as per the reaction

6.8*10-2 M Al2(SO4)3 correspond to 2*6.8*10^-3 M Al+3= 13.6*10-3 M Al+3

Part D

Na3PO4-------->3Na++ PO4-3

1M Na3PO4 correspond to 3 M Na+

0.190M Na3PO4 correspond to 3*0.19= 0.57M Na+