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given a diprotic acid, H2A, with two ionization constants of Ka1 = 1.6×10^-4 and Ka2 =...

given a diprotic acid, H2A, with two ionization constants of Ka1 = 1.6×10^-4 and Ka2 = 5.2×10^-11, calculate the ph for a .206 M solution of NaHA

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Answer #1

Since we neglect second dissociation and consider the diprotic acid as monoprotic acid for our calculation.

Initial concentration (M) 0.206 0 0
Change in concentration (M) -x x x
Equilibrium concentration (M) 0.206-x x x

The equilibrium constant

Since the value of Kb is small, we use the approximation

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