Question

If a student weighs out 0.482 grams of aluminum foil and dissolves it in KOH solution,...

If a student weighs out 0.482 grams of aluminum foil and dissolves it in KOH solution, how many moles of aluminum metal react?

How many moles of KOH are necessary to react with the aluminum metal?

Calculate the number of moles of KOH in 13.0 mL of 3.0 M KOH solution?

Homework Answers

Answer #1

2Al(s) + KOH + 6H2O -------------> 2KAl(OH)4 + 3H2

no of moles of Al = W/G.A.Wt

                              = 0.482/27   = 0.0178moles

no of moles of KOH = molarity * volume in L

                                  = 3*0.013   = 0.039 moles

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