Estimate the free energy change (?Grxn) for the following reaction at 298 K, if each gaseous substance is present at p = 0.25 atm.
C2H5OH(l) + 3O2(g) ? 2CO2(g) + 3H2O(l)
Enter your answer in kJ.
ENTHALPY OF REACTION
[2ΔHf(CO2 (g)) + 3ΔHf(H2O (g))] - [1ΔHf(C2H5OH (ℓ ethanol)) + 3ΔHf(O2 (g))]
[2(-393.51) + 3(-241.82)] - [1(-276.98) + 3(0)] = -1235.5 kJ
-1,235.50 kJ (exothermic)
ENTROPY CHANGE
[2ΔSf(CO2 (g)) + 3ΔSf(H2O (g))] - [1ΔSf(C2H5OH (ℓ ethanol)) + 3ΔSf(O2 (g))]
[2(213.68) + 3(188.72)] - [1(161.04) + 3(205.03)] = 217.39 J/K
217.39 J/K (increase in entropy)
FREE ENERGY OF REACTION (AT 298.15 K)
From ΔGf° values:
[2ΔGf(CO2 (g)) + 3ΔGf(H2O (g))] - [1ΔGf(C2H5OH (ℓ ethanol)) + 3ΔGf(O2 (g))]
[2(-394.38) + 3(-228.59)] - [1(-174.18) + 3(0)] = -1300.35 kJ
-1,300.35 kJ (spontaneous)
From ΔG = ΔH - TΔS:
-1300.31 kJ (spontaneous)
EQUILIBRIUM CONSTANT, K (AT 298.15 K)
6.6702167631e+227
This process is favorable at 25°C.
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