Use Hess's Law combining the three molecular equations to calculate the heat of reaction (delta H "rxn") for the reaction of the formation of MgO.
molecular equation : Mg (s) + 2 HCl (aq) -----> MgCl2 (aq) + H2 (g)
molecular equation : MgO(s) + 2HCl(aq) ----> H2O(l) + MgCl2(aq)
molecular equation: Mg (s) + 1/2 O (g) ----> MgO(s)
Ht=H1+H2+H3
1) Delta H=?
2) Delta H=?
3) Delta H=?
you just have to add the enthalpies of each stage, but as the data left on your table can not answer so if you want you give an example and investigate you and only you substitute data.
This reaction may occur as we have written, in one step, or can also occur in two stages. In a first stage carbon monoxide, CO, is formed and then, once formed carbon monoxide, it returns to react with oxygen to form CO2. The stages are:
The detached total energy in the formation of 1 mole of CO2 is the same whether it occurs in a stage as two, as to determine the total energy released when given in two stages simply add the enthalpy changes of the steps in which elapses.
ΔH1 = ΔH2 + ΔH3
-393,5 = -110,4 + (-283,1)
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