Deterine the heat of vaporization per mole of bromine.
Thank you, I thought there wasnt enough info!!. These high school Chem teachers need to check their questions before they hand them out !!
We will try to solve this problem by taking some literature values
Solid to liquid ----- fusion
liquid to gas ------- vaporization
solid to gas -------- sublimation
Or,
solid to liquid to gas ----- combination of fusion and vaporization
Now from literature we know,
with dH = enthalpy
dH(fusion) for Br2 = 10.6 kJ/mol
and,
dH(sublimation) = 40.1 kJ/mol
So,
dH(sublimation) = dH(fusion) + dH(vaporization)
substituting the values from above,
dH(vaporization) per mole of bromine = 40.1 - 10.6 = 29.5 kJ/mol
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