Question

Q =

2.7×10−27

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Correct

The reaction quotient is Q=2.7×10−27.

For any Q value less than this, E will be positive and therefore the reaction will favor products.

Part B

What pH is needed to produce this value of Q if the concentration and pressure values are

[Br2]=3.50×10−4M,

[Br−]=12.35M,

[SO42−]=8.40M, and

PSO2=1.00×10−5atm?

Need help with part b, the pH, thanks

Answer 1

The reaction quotient is Q = 2.7* 10⁻²⁷

Q = ([Br₂] *[P_SO2])/ ([SO₄^2-] * [Br^-]² * [H⁺]⁴)

2.7* 10⁻²⁷ = (3.50×10⁻⁴ * 1.00×10⁻⁵ )/ (8.40 * (12.35)² * [H⁺]⁴)

2.7* 10⁻²⁷ = (3.50 * 10^-9) / ( 1281.189 * [H⁺]⁴)

2.7* 10⁻²⁷ * ( 1281.189 *[H⁺]⁴) = (3.50 * 10^-9 )

3459.2103 *10⁻²⁷ *  [H⁺]⁴ = (3.50 * 10^-9 )

[H⁺] = (3.50 * 10^-9 / 3459.2103 *10⁻²⁷ )^1/4

[H⁺] = (1.011 *10¹⁵)^1/4

[H⁺] =  5639.91744 M

pH = -log [H⁺] = - log [5639.91744]

so
pH = -3.75

yes, pH can be negative