Question

32P is a radioactive isotope with a half-life of 14.3 days. If you currently have 82.7 g of 32P, how much 32P was present 5.00 days ago?

Please show detailed steps

Answer 1

K   = 0.693/t1/2

       = 0.693/14.3

        = 0.04846days^-1

K   = 2.303/t log[A0]/[A]

0.04846 = 2.303/5 log82.7/[A]

log82.7/[A]    = 0.04846*5/2.303

log82.7/[A]     = 0.1052

82.7/[A]        = 10^0.1052

82.7/[A]         = 1.274

[A]                  = 82.7/1.274   = 65g >>>>answer