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A reaction was studied at various temperatures, and data below was collected. Determine the activation energy...

A reaction was studied at various temperatures, and data below was collected. Determine the activation energy of the reaction, as well as the missing temperature.

T(°C) K
1 57
24 134
? 75
Science   Chemistry   
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Homework Answers

Answer #1

1)

T1 = 1.0 oC

=(1.0+273)K

= 274.0 K

T2 = 24.0 oC

=(24.0+273)K

= 297.0 K

K1 = 57

K2 = 1.34*10^2

use:

ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)

ln(1.34*10^2/57) = ( Ea/8.314)*(1/274.0 - 1/297.0)

0.8548 = (Ea/8.314)*(2.826*10^-4)

Ea = 25145 J/mol

Ea = 25.145 KJ/mol

Answer: 25.145 KJ/mol

2)

T1 = 1.0 oC

=(1.0+273)K

= 274.0 K

K1 = 57

K2 = 75

Ea = 25.145 KJ/mol

= 25145 J/mol

use:

ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)

ln(75/57) = (25145/8.314)*(1/274.0 - 1/T2)

0.2744 = 3024.4166*(1/274.0 - 1/T2)

T2 = 281

= (281-273) oC

= 8 oC

Answer: 8 oC

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