Question

14. Determine the molarity of a solution made by dissolving 1.21 moles of CaCl2 in enough water to make 250.0 mL of solution. (___M CaCl2

15. Determine the molarity of a solution made by dissolving 34.3 g of Sr(ClO3)2 in enough water to make 250.0 mL of solution. (___ M Sr(ClO3)2

16. Determine the volume (in mL) of a 1.62 M solution of ZnBr2 that contains 0.299 moles of ZnBr2.

(____ mL)

17. Determine the mass of solute (in g) contained in 250.0 mL of a 2.17 M solution of AlF3. (___gAlF3

Answer 1

14. molarity = moles / volume of solution (in litre) [ 1litre = 1000 ml]

= 1.21/ (0.250)

= 4.84 M

15. moles of Sr(ClO3)2 = mass / molar mass

= 34.3 / 255

= 0.1345 moles

molarity = 0.1345 / 0.250

= 0.538 M

16 . moles / molarity = volume(in litre)

= 0.299 / 1.62

= 0.18457 litre

184.57 ml

17. moles = molarity*volume(in litre)

= 2.17*0.250

= 0.5425 moles

mass of alf3 = moles * molar mass

= 0.5425* 84

= 45.57 grams

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