Question

Chlorine gas reacts explosively with sodium to form sodium chloride. How many grams of sodium chloride can be produced from O.745 L of chlorine gas measured at 1.21 atm and 22 °C assuming 100% reaction?

Answer 1

the reaction taking place is:
Cl2 + 2 Na —> 2 NaCl

1st find the mol of Cl2 reacting
Given:
P = 1.21 atm
V = 0.745 L
T = 22.0 oC
= (22.0+273) K
= 295 K

find number of moles using:
P * V = n*R*T
1.21 atm * 0.745 L = n * 0.08206 atm.L/mol.K * 295 K
n = 3.724*10^-2 mol

from reaction,
mol of NaCl2 formed = 2*moles of Cl2 reacted
= 2*3.724*10^-2 mol
= 7.448*10^-2 mol

Molar mass of NaCl,
MM = 1*MM(Na) + 1*MM(Cl)
= 1*22.99 + 1*35.45
= 58.44 g/mol

use:
mass of NaCl,
m = number of mol * molar mass
= 7.448*10^-2 mol * 58.44 g/mol
= 4.35 g
Answer: 4.35 g