If the molar solubility of MnCO3 is 1.4*10-6 M at a certain temperature, what is the Ksp for the compound
MnCO3(s) --------------------> Mn^2+ (aq) + CO3^2- (aq)
s s
Ksp = [Mn^2+][CO3^2-]
Ksp = s*s
Ksp = s^2
= (1.4*10^-6)^2
= 1.96*10^-12 >>>>>answer
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