Question

Mg(OH₂) a base reacts with HCl(acid) as follows

Mg(OH)₂+HCl -> MgCl₂+H₂O

How many militers of 0.2m HCl are required to neutralize 50mL Mg(OH)₂?

first find the molarity

Answer 1

The balanced equation is

Mg(OH)2 + 2HCl -> MgCl2 + 2H2O

volume of Mg(OH)2 = 50 / 1000 = 0.05 L

22.4 L = of Mg(OH)2 = 1 mole so

0.05 L of Mg(OH)2 = 0.00223 mole

from the balanced equation we can say that

1 mole of Mg(OH)2 requires 2 mole of HCl so

0.00223 mole of Mg(OH)2 will require 0.00446 mole of HCl

molarity of HCl =number of moles of HCL / volume of solution inL

0.2M = 0.00446 / volume of solution in L

volume of solution in L = 0.00446 / 0.2 = 0.0223 L

1L = 1000 mL

0.00223 mL = 22.3 mL

Therefore, the number of milli litters of HCl required would be 22.3 mL