The mass of the atom 23
11 Na is 22.9898 amu.
a) Calculate its binding energy per atom in millions of electron
volts.
b) Calculate its binding energy per nucleon.
a) m = theoretical mass = Z X mH + (A - Z) mn
where, Z = atomic number, A = mass number, mH = mass of proton, mn = mass of nutron
mass of proton = 1.007825 u . mass of nutron = 1.008665 u
Z for Cu = 23 then (A - Z ) = 23 - 11 = 22
substitute value
( 11X 1.007825) + (12 X 1.008665) = 23.190055 u
m = m - m' where, m = mass defect
= 23.190055 - 22.9898 = 0.200255 u
binding energy = m X 931.5
= 0.200255 X 931.5 = 186.5375325 MeV
Binding energy per atom = 186.5375325 MeV
b) binding energy/nucleon = binding energy/ mass number
= 186.5375325 / 23
= 8.11 MeV
binding energy/nucleon = 8.11 MeV
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