Question

Sketch the titration curve that would result if the fully unprotonated form of cysteine were titrated...

Sketch the titration curve that would result if the fully unprotonated form of cysteine were titrated with HCl. Label midpoints, equivalence points and indicate which part of the titration corresponds to each of the specific pKa values of cysteine

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Answer #1

The structure of cysteine (SH-CH2-CH(NH3+)(COO-) at pH = 7 shows that the side group is protonated even though the pKa is 8.33, the sulfhydryl (−SH) is acting as an acid.

In alkaline solutions, 1.96 < pH < 8.33, the carboxylic acid sheds its proton in order to neutralize OH-

pH = pKa1 = acidic

pH = pI = netrual

pH = pKa2= basic

As shown in following two images:

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