If 2.00 kg of nitroglycerin is detonated at STP, how many liters of products are formed? Nitroglycerin detonates according to the balanced reaction:
4C3H5N3O9 (l) --> 12CO2 (g) + 6N2 (g) + O2 (g) + 10H2O (g)
Molar mass of C4H5N3O9 = 4*MM(C) + 5*MM(H) + 3*MM(N) + 9*MM(O)
= 4*12.01 + 5*1.008 + 3*14.01 + 9*16.0
= 239.11 g/mol
mass of C4H5N3O9 = 2000 g
mol of C4H5N3O9 = (mass)/(molar mass)
= 2000/239.11
= 8.3644 mol
From balanced chemical reaction, we see that
when 4 mol of C4H5N3O9 reacts, 29 mol of gas is formed
mol of gas formed = (29/4)* moles of C4H5N3O9
= (29/4)*8.3644
= 60.6415 mol
Molar volume at STP = 22.4 L
So,
volume = number of mol * molar volume
= 60.6415 mol * 22.4 L/mol
= 1358 L
Answer: 1358 L
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