9.35 Determine the pH of water solutions with the following characteristics. Classify
each solution as acidic, basic, or neutral.
a) [H+] = 1.0 x10-4 M
b) [OH-] = 5.0 x10-2 M
c) [H+] = [OH-]
d) [H+] = 8.0 x10-9 M
e) [OH-] = 4.0 x10-10 M
a) pH = -log[H+] = -log(1.0 X 10-4) = 4
solution is acidic
b) pOH = -log[OH-] = -log(5.0 X 10-2) = 1.30
pH = 14 - pOH = 14 - 1.30 = 12.70
solution is besic
c) [H+] = [OH-]
[H+] = [OH-] = x
[H+] X [OH-] = 1 X 10-14
x2 = 1 X 10-14
x = 1 X10 -7
[H+] = 1 X10 -7
pH = -log[H+] = -log(1.0 X 10-7) = 7
solution is neutral
d)
[H+] = 8.0 X10 -9
pH = -log[H+] = -log(8.0 X 10-9) = 8.09
solution is Besic
e)
pOH = -log[OH-] = -log(4.0 X 10-10) = 9.4
pH = 14 - pOH = 14 - 9.4 = 4.6
solution is Acedic
pH = 1 to 7 solution acedic
pH = 7 solution neutral
pH = 7 to 14 solution besic
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