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The reaction N2 + 3 H2----> 2 NH3 is used to produce ammonia. When 450.0 g...

The reaction N2 + 3 H2----> 2 NH3 is used to produce ammonia. When 450.0 g of hydrogen was reacted with nitrogen, the percent yield you achieved was 30.8%. What was the mass of ammonia produced?

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Answer #1

Molar mass of H2 = 2.016 g/mol

mass of H2 = 450 g

mol of H2 = (mass)/(molar mass)

= 450/2.016

= 223.2143 mol

From balanced chemical reaction, we see that

when 3 mol of H2 reacts, 2 mol of NH3 is formed

mol of NH3 formed = (2/3)* moles of H2

= (2/3)*223.2143

= 148.8095 mol

Molar mass of NH3 = 1*MM(N) + 3*MM(H)

= 1*14.01 + 3*1.008

= 17.034 g/mol

mass of NH3 = number of mol * molar mass

= 148.8095*17.034

= 2534.8214 g

% yield = actual mass*100/theoretical mass

30.8= actual mass*100/2534.8214

actual mass= 781 g

Answer: 781 g

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