Give pH of the following:
Part C: [OH−]=7×10−2M
Part D:[OH−]=7.0×10−3M
Part E:[H3O+]=5.8×10−2M
Part F:[OH−]=8.4×10−6M
express answer using two decimal places.
C)
we have below equation to be used:
pOH = -log [OH-]
= -log (7*10^-2)
= 1.1549
we have below equation to be used:
PH = 14 - pOH
= 14 - 1.1549
= 12.8451
Answer: 12.84
D)
we have below equation to be used:
pOH = -log [OH-]
= -log (7*10^-3)
= 2.1549
we have below equation to be used:
PH = 14 - pOH
= 14 - 2.1549
= 11.8451
Answer: 11.84
E)
we have below equation to be used:
pH = -log [H3O+]
= -log (5.8*10^-2)
= 1.2366
Answer: 1.24
F)
we have below equation to be used:
pOH = -log [OH-]
= -log (8.4*10^-6)
= 5.0757
we have below equation to be used:
PH = 14 - pOH
= 14 - 5.0757
= 8.9243
Answer: 8.92
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