Question

Molarity: Determine the concentration of the following solutions. 1. 35 moles of sodium chloride dissolved in...

Molarity: Determine the concentration of the following solutions.

1. 35 moles of sodium chloride dissolved in a final volume of 9.5L will produce a sodium chloride solution with what concentration?

2. If you dissolve 12g of sodium hydroxide in a final volume of 5L, what is the concentration of the resulting solution?

3. If you dissolve 12g of sodium hydroxide in a final volume of 125ml, what is the concentration of the resulting soltuion?

4. If you dissolve 0.012 moles of sodium acetate in 12.6mL, what is the concentration of the resulting solution?

5. If you have 325mL of a 6.2M solution of sodium acetate, how many grams of sodium acetate are dissolved in that solution?

6. If you dissolve 23.9g of sodium acetate in 12.5mL, what is the concentration of the resulting solution?

7. If you have 129.6g of hydroiodic acid dissolved in 4.5L of water, what is the final concentration of your solution?

8. What is the concentration of glucose in a cola if 66g of glucose are dissolved in 250mL of solution?

9. If you have 334g of sulfuric acid dissolved in 24.5mL, what is the concentration of that solution?

10. What mass of hydrochloric acid is required to prepare 14.5L of a 0.606M solution?

Please write out each step, to help me better understand how to solve these problems. Thank you so much! Could you also, please, type out your response so I can legibly read it. Thank you!

Homework Answers

Answer #1

1. Molarity = moles of solute/Volume in L of solvent

moles = 35moles

Volume = 9.5L

Molarity = 35moles/9.5L = 3.68mol/L

2. Mass of NaOH = 12g

Molar mass of NaOH = 40g/mol

moles of NaOH = mass/molar mass = 12g/ 40g/mol = 0.3moles

Volume = 5L

Molarity = 0.3moles/5L = 0.06mol/L

3. Mass = 12g

Molar mass of NaOH = 40g/mol

Moles = 12g/40g/mol = 0.3moles

Volume = 125L

Molarity = 0.3moles/125L = 0.0024mol/L

4. Moles = 0.012moles

Volume = 12.6mL = 12.6/1000L = 0.0126L

Molarity = 0.012mol/0.0126L = 0.952mol/L

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