If hydrogen were used as a fuel, it could be burned according to
the following reaction:
H2(g)+1/2O2(g)→H2O(g)
Use average bond energies to calculate ΔHrxn for this reaction.
The deltaHrxn = -243 kJ/mol the deltaHrxn of CH4(methane) = -802 kJ/mol
The fuel that yields more energy per mole is METHANE. The negative sign merely signifies the release of energy. Thus, 802 kJ/mol is greater than 243 kJ/mol.
The fuel that yields more energy per gram is HYDROGEN. Here is the computation:
deltaHrxn = (-243 kJ/mol)(1 mol/2.016 g H2) = -120.535714286 kJ/g or -121 kJ/g
deltaHrxn of CH4(methane) = (-802 kJ/mol)(1 mol/16.04 g)
= -50 kJ/g
As discussed the negative sign serves as the symbol of released energy. Thus, 121 is greater than 50.
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