Question

Charles's Law:

a.) A sample of krypton gas at a pressure of 1.02 atm and a
temperature of 167 ^{o}C, occupies a volume of 587 mL. If
the gas is heated at constant pressure until its volume is 849 mL,
the temperature of the gas sample will be
__________^{o}C.

b.) A sample of methane gas at a pressure of 683 mm Hg and a
temperature of 79 ^{o}C, occupies a volume of 13.4 liters.
If the gas is cooled at constant pressure to a temperature of 29
^{o}C, the volume of the gas sample will be
__________L.

c.) A sample of helium gas at a pressure of 1.06 atm and a
temperature of 169 ^{o}C, occupies a volume of 836 mL. If
the gas is heated at constant pressure until its volume is 1.13 x
10^{3} mL, the temperature of the gas sample will be
__________^{o}C.

Answer #1

a)

we have:

T1 = 167.0 oC

= (167.0+273) K

= 440 K

V1 = 587 mL

V2 = 849 mL

we have below equation to be used:

V1/T1 = V2/T2

587.0 mL / 440.0 K = 849.0 mL / T2

T2 = 636.3884 K

T2 = 363 oC

Answer: 363 oC

b)

we have:

V1 = 13.4 L

T1 = 79.0 oC

= (79.0+273) K

= 352 K

T2 = 29.0 oC

= (29.0+273) K

= 302 K

we have below equation to be used:

V1/T1 = V2/T2

13.4 L / 352.0 K = V2 / 302.0 K

V2 = 11.5 L

Answer: 11.5 L

c)

we have:

T1 = 169.0 oC

= (169.0+273) K

= 442 K

V1 = 836 mL

V2 = 1130 mL

we have below equation to be used:

V1/T1 = V2/T2

836.0 mL / 442.0 K = 1130.0 mL / T2

T2 = 597.4402 K

T2 = 324 oC

Answer: 324 oC

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