Question

Absorbance	Initial concentrations			Concentrations at equilibrium		Kc*
	[Fe3+]o	[SCN-]0	[FeSCN2+]eq	[Fe3+]eq	[SCN-]eq
(au)	(M)	(M)	(M)	(M)	(M)	(M-1)
.888	0.200	.00200	0.00200
.250	0.001	0.0004	0.0000600	0.000940	0.00034	187.5
.420	0.001	0.0006	0.000100	0.000900	0.000500	222.2
.520	0.001	0.0008	0.000124	0.000876	0.000676	209.46
.640	0.001	0.001	0.0001535	0.0008465	0.0008465	214.38
					Average	208.385

To obtain [FeSCN²⁺]_eq in tube 5, you made the assumption that 100% of the ions SCN^– had reacted. Now that you know the value for K_{c (}(208.385), build an ICE diagram to calculate the true percentage of SCN^– reacted in tube 5.
Tube 5 is the one with .888 Au
How do I find the true percentage of SCN-?

Answer 1