balanced chemical reaction is
Ca(NO3)2 + Na2CO3 CaCO3 + 2NaNO3
first calculate theoretical yield
molar mass of Ca(NO3)2 = 164.088 gm/mole then 87.5 gm of Ca(NO3)2 = 87.5 / 164.088 = 0.533 mole
According to reaction 1 mole of calcium nitrare produce 1 mole of calcium carbonate then 05333 mole of calcium nitrare produce 0.533 mole of calcium carbonate
molar mass of calcium carbonate = 100.0869 gm/mole then 0.533 mole of calcium carbonate = 0.533 X 100.0869
= 53.37 gm
53.37 gm calcium carbonate is theoretical yield
percentange yield = actual yield X 100 / theoretical yield
percentage yield of calcium carbonate = 87.69 %
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