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If you make 46.8g of calcium carbonate by reacting 87.5g of calcium nitrate with plenty of...

If you make 46.8g of calcium carbonate by reacting 87.5g of calcium nitrate with plenty of sodium carbonate, what is your percent yield?
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Answer #1

balanced chemical reaction is

Ca(NO3)2 + Na2CO3   CaCO3 + 2NaNO3

first calculate theoretical yield

molar mass of Ca(NO3)2 = 164.088 gm/mole then 87.5 gm of Ca(NO3)2 = 87.5 / 164.088 = 0.533 mole

According to reaction 1 mole of calcium nitrare produce 1 mole of calcium carbonate then 05333 mole of calcium nitrare produce 0.533 mole of calcium carbonate

molar mass of calcium carbonate = 100.0869 gm/mole then 0.533 mole of calcium carbonate = 0.533 X 100.0869

= 53.37 gm

53.37 gm calcium carbonate is theoretical yield

percentange yield = actual yield X 100 / theoretical yield

percentage yield of calcium carbonate = 87.69 %

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