Question

Given the following groundwater analysis at 25 degrees , Ca2+ = 83.27 mg/L HCO3-= 366.78 mg/L...

Given the following groundwater analysis at 25 degrees , Ca2+ = 83.27 mg/L HCO3-= 366.78 mg/L Mg2+ =24.32 mg/L Cl- =12.50 mg/L Na+ =18.33 mg/L K+=2.34 mg/L SO42- = 23.45 mg/L   pH =7.8 TDS=542 mg/L

a) Convert all analytical results into molal concentrations.

b) Compute the ionic strength.

c) Compute the activity coefficient for each ion.

d) Find the activity for each ion.

e) Converts analytical results to meq/L.

f) Perform a cation-anion balance calculation.

g) Find the Kiap of anhydrite (CaSO4).

h) Compare the Kiap of anhydrite with the Ksp of anhydrite (10^-4.5).

i) Find the Kiap of calcite (CaCO3).

j) Compare the Kiap of calcite with the Ksp of calcite (10^-8.4).

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