Question

Consider a situation in which 235 g of P4 are exposed to 272 g of O2.

What is the maximum number of moles of P2O5 that can theoretically be made from 235 g of P4 and excess oxygen?

What is the maximum number of moles of P2O5 that can theoretically be made from 272 g of O2 and excess phosphorus?

Express your answer to three significant figures and include the appropriate units.

Answer 1

Balanced chemical reaction is

P₄ + 5O₂   2P₂O₅

# molar mass of P₄ = 123.90 gm/mole

then 235 gm of P₄ = 235/123.90 = 1.897 mole

According to reaction 1 mole of P₄ produe 2 mole of then 1.897 mole of P₄ produce 1.897 X 2 = 3.79 mole of P₂O₅

3.79 mole of P₂O₅ produced

# molar mass of P₄ = 123.90 gm/mole

then 272 gm of P₄ = 272/123.90 = 2.195 mole

According to reaction 1 mole of P₄ produe 2 mole of then 1.897 mole of P₄ produce 2.195 X 2 = 4.39 mole of P₂O₅

4.39 mole of P₂O₅ produced