When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation
1. What mass of silver chloride can be produced from 1.97 L of a 0.285 M solution of silver nitrate?
2.The reaction described in Part A required 3.62 L of calcium chloride. What is the concentration of this calcium chloride solution?
calculate mol of Silver nitrate, AgNO3
mol = MV = 1.97*0.285 = 0.56145 mol of AgNO3
ratio is 2:2 or 1:1 with reswpect to AgNO3 and AgCl
mol of AgCl = 0.56145mol
MW of AgCl = 143.32 g/mol
mass = mol*MW = 0.56145*143.32 = 80.467014 g
V = 3.62 L of CaCl2 solution...
relate to mol of CaCl2
2:1 ratio of AgNO3:CaCl2
0.56145 mol of AgNO3 --> 1/2*0.56145 = 0.280725 mol of CaCl2
M = mol/V = 0.280725 /(3.62) = 0.0775483 M of CaCl2
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