Question

If t_calc is less than t_crit for a given confidence level, then the measured value is in agreement with the true, accepted value.

The following data is in mg/ml:

0.342, 0.317, 0.335, 0.322, and 0.319. The accepted value is 0.331 mg/ml. Determine whether the measured average agrees with the accepted value at 95% confidence.

Answer 1

You can make a t test analysis

here you have to apply the equation

t = x_mean - X_accepted / (s /

x mean is the mean

s is the standard deviation of the sample (not the population)

n is the number of samples

Im getting a mean value of 0.327

standard deviation of the sample is 0.01093

n is 5

so t is = 0.327 - 0.331 / ( 0.01093 / ) = -0.818 we take the absolute value which is

t = 0.818

Now we must look for the t value on the t student chart for one sided tail

so alpha is 1 - 0.95 = 0.05

freedom degrees is n - 1 = 5 - 1 = 4

the t (0.05, 4) = 2.132

so our t calc (0.818) is less than t crit (2.132) so we say that our mean sample agrees with the accepted value

*please rate the answer if you like it =)