Question

1a. The pOH of an aqueous solution at 25°C was found to be 5.10.

The pH of this solution is ____.

The hydronium ion concentration is ____M.

The hydroxide ion concentration is ____M.

1b. The pH of an aqueous solution at 25°C was found to be 10.00.

The pOH of this solution is ______.

The hydronium ion concentration is ____ M.

The hydroxide ion concentration is ____M.

Answer 1

a)

we have below equation to be used:

PH = 14 - pOH

= 14 - 5.1

= 8.9

we have below equation to be used:

pH = -log [H+]

8.9 = -log [H+]

log [H+] = -8.9

[H+] = 10^(-8.9)

[H+] = 1.259*10^-9 M

we have below equation to be used:

pOH = -log [OH-]

5.1 = -log [OH-]

log [OH-] = -5.1

[OH-] = 10^(-5.1)

[OH-] = 7.943*10^-6 M

[H+] = 1.259*10^-9

[OH-] = 7.943*10^-6

pH = 8.9

b)

POH = 14 - pH

= 14 - 10

= 4

we have below equation to be used:

pH = -log [H+]

10 = -log [H+]

log [H+] = -10

[H+] = 10^(-10)

[H+] = 1*10^-10 M

we have below equation to be used:

pOH = -log [OH-]

4 = -log [OH-]

log [OH-] = -4

[OH-] = 10^(-4)

[OH-] = 1*10^-4 M

[H+] = 1*10^-10

[OH-] = 1*10^-4

pOH = 4