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#21. (a) What is the molar heat capacity of liquid water? 75.2 J/mol oC (this one...

#21.

(a) What is the molar heat capacity of liquid water?

75.2 J/mol oC (this one is correct just need help with B and C)




(b) What is the heat capacity of 8.58 mol of liquid water?

___kJ



(c) How many kJ of heat are needed to raise the temperature of 3.02 kg of water from 35.9 oC to 74.9 oC?

___kJ

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Homework Answers

Answer #1

(b)

The molar heat capacity of liquid water is 75.348 J/mol K. This means that each mole of liquid water requires 75.348 Joules of heat energy to raise its temperature by one degree Kelvin.

So. 8.58 mol of liquid water requires (8.58 x 75.348) Joules.

8.58 mol of liquid water requires 646.486 J.

8.58 mol of liquid water requires 0.646 kJ.

(c)

We know that

q = mass x specific heat of watet x change in temperature

  q = m x CH2O x T

mass, m = 3.02 Kg = 3020 g

T = 74.9 oC - 35.9 oC = 39 oC

specfic heat liquid, CH2O = 4.184 J/g oC

Substituting the above values, we get

  q = m x CH2O x T

q = 3020 g x 4.184 J/(g oC) x 39 oC

q = 492791.5 J

q = 492.79 kJ

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