Question

1) calculate and compare the differences in volume when a given amount of gas doubles in temperature from

a) 200k to 400k b)200c to 400c

2) how is ionization energy diff from electron affinity?

3)give the abbreviated electron configuration for the +2 ion of zinc

Answer 1

1s2, 2s2 2p6, 3s2 3p6 At constant pressure

PV= nRT

Since pressure is consrtant

V1/T1= V2/T2

V1/200= V2/400

V2= 400V1/200= 2V1 ( voume also gets doubled)

V1/T1= V2/T2

T1= 200 deg.c =200+273.15 K =473.15K

T2= 400deg.c =400+273.15K=673.15

V1/473.15 =V2/ 673.15

V2= V1*673.15/473.15

V2=1.422699V1

2.

Ionization energy is the amount of energy required to remove an electron from a neutral atom leading to formation of positively charged ion.

Electron affinity is the energy given when a neutral atom in gaseous phase picks up an electron and becomes negatively charged.

3. The electronic configuration of Zn is [Ar] 3d¹⁰ 4S²

the electronic configuration of Ar is 1s² 2s² 2p⁶ 3s²3p⁶

For Zn+2 two electrons will have to be removed Zn+2 electronic configuration is [Ar] 3d¹⁰