Question

1. Complete the following nuclear equations:

A. ------------->   ^96₄₁  NB + ⁴₂ HE + ¹_{0 n}

_B. ²⁶⁶₁₀₆ Sg + ⁰_-1 e -------------> + ⁴₂ He

Answer 1

1)

Let the reactant be X

Balance mass number on both sides

mass of X = mass of Nb + mass of He + mass of n

M = 1*96 + 1*4 + 1*1

M = 101

Balance atomic number on both sides

atomic of X = atomic of Nb + atomic of He + atomic of n

A = 1*41 + 1*2 + 1*0

A = 43

Atomic number 43 is for element Tc

So, the reactant is

101-Tc

Answer: ¹⁰¹₄₃Tc is missing reactant

2)

Let the product be X

Balance mass number on both sides

mass of Sg + mass of e = mass of He + mass of X

1*266 + 1*0 = 1*4 + M

M = 262

Balance atomic number on both sides

atomic of Sg + atomic of e = atomic of He + atomic of X

1*106 + 1*-1 = 1*2 + A

A = 103

Atomic number 103 is for element Lr

So, the product is

262-Lr

Answer: ²⁶²₁₀₃Lr is missing product