NaCl is a “face-centered” ionic crystal with a unit
cell side length of 564 pm. Find the volume in cm3 of the
empty space inside one NaCl unit cell (aka. interstitial sites)
face centred means 1/2 part of phere in each face and cube has 6 faces so total sphere is 3.and 1/8 part of each sphere at its each corneer so from here we have 8* 1/8 = 1 sphere
total sphere = 4
now raius is linked with the unit cell length = r = A/2* 2^1/2 (A=564 pm)
r= 564/2*2^1/2 = 199.4 pm
now volume covered by 4 spheres = 4 * 4/3 * 3.14 *r^3
= 4* 4/3 * 3.14 *199.4^3= 133772474 pm^3
now volume of unit cell = A ^3 =564^3 = 179406144 pm^3
now empty space = unit cell 's volume - total volumes of sphere
= 179406144-133772474= 45633670 pm ^3
HERE ANSWERS MAY BE IN DIFFERENT UNITS PLEASE FOLLOW AND UNDERSTAND THE PROCESS
IF U SATISFY WITH THE SOLUTION PLEASE LIKE IT ............THNKXXXXX
Get Answers For Free
Most questions answered within 1 hours.