Question

If you had 25.00 mL of an tosic acid solution that had a concentration of 4.556 g per liter, how many milliliters of 0.396 M NaOH would it take to completely react with all the tosic acid present? Tosic acid is a monoprotic acid and has a molar mass of 172.2 g/mol.

Answer 1

Tosic acid molar mass = 172.2 gm/mol

then 4.556 gm tosic acid = 4.556 / 172.2 = 0.02646 mole

concnetration of tosic acid = 0.02646 mole / liter = 0.02646 M

25 ml = 0.025 L

no. of mole = molarity X volume of solution in liter

no. of mole of tosic acid in 25 ml = 0.02646 X 0.025 = 0.00066 mole

Tosic acid is monoprotic acid therefore react with NaOH in equimolar proportion thus to react with 0.00066 mole of tosic acid requied mole of NaOH = 0.00066 mole

volume of solution in liter = no. of mole / molarity

volume of NaOH solution required = 0.00066 / 0.396 = 0.00167 L

0.00167 L = 1.67 ml

1.67 mililiter NaOH  would it take to completely react with all the tosic acid