Question

Use molar volume to calculate each of the following at STP:

Part A

the volume, in liters, occupied by 2.60 moles of N2 gas

Part B

the number of moles of CO2 in 4.30 L of CO2 gas

_______

A 10.0 g sample of krypton has a temperature of 25∘C at 565 mmHg .

Part C

What is the volume, in milliliters, of the krypton gas?

Express your answer to three significant figures and include the appropriate units.

Answer 1

Molar volume = 22.4 L/mol

A)

number of mol = 2.60 mol

use:

volume = number of mol * molar volume

= 2.60 mol * 22.4 L/mol

= 58.2 L

Answer: 58.2 L

B)

mol of CO2 = volume / molar volume

= 4.30 L / 22.4 L/mol

= 0.192 mol

Answer: 0.192 mol

C)

Molar mass of Kr = 83.8 g/mol

mass(Kr)= 10.0 g

use:

number of mol of Kr,

n = mass of Kr/molar mass of Kr

=(10 g)/(83.8 g/mol)

= 0.1193 mol

Given:

P = 565.0 mm Hg

= (565.0/760) atm

= 0.7434 atm

n = 0.1193 mol

T = 25.0 oC

= (25.0+273) K

= 298 K

use:

P * V = n*R*T

0.7434 atm * V = 0.1193 mol* 0.08206 atm.L/mol.K * 298 K

V = 3.92 L

V = 3920 mL

Answer: 3920 mL