Use bond energies to estimate the heat for the
combustion of 2.6 g of acetylene gas C2H2 to form carbon
dioxide and water vapor.
Balanced combuiton reaction is
2C2H2 + 5O2 4CO2 + 2H2O
Bond enthalpy of
C C = 963 kJ/mol
O = O = 498 KJ/mol
C - H = 414 kJ/mol
O - H = 465 kJ/mol
C = O = 532 kJ/mol
H0 = H0 (Reactant bonds) - H0 (product bonds)
H0 = [2 H0(C C) + 4H0(C - H) + 5H0(O = O) ] - [8H0(C = O) + 4H0(O - H) ]
Substitute the bond enthalpy in above equation
[2(963 kJ/mol) + 4( 414 kJ/mol) + 5(498)] - [8(532 kJ/mol) + 4( 465 kJ/mol) ]
(6072 kJ/mol) - (6116) = -44 kJ/mol
H0 for your reaction is = -44 kJ/mol
-44 kJ/mol is for combution of 2 mole of C2H4
molar mass of C2H4 = 28.05 gm/mole then 2 mole C2H4 = 2 X 28.05 = 56.1 gm
for combution of 56.1 gm C2H4H0 for your reaction is = -44 kJ/mol then for 2.6 gm C2H4H0 for your reaction is = -44 X 2.6 / 56.1 = -2.04 KJ
for coombution of 2.6 gm acetylene gas H0 = -2.04 KJ
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