Question

Calculate the amount of energy (in kJ) required to heat 10.0 g of water from 50.0°C...

Calculate the amount of energy (in kJ) required to heat 10.0 g of water from 50.0°C to 150.°C at constant pressure. (specific heat capacity of liquid water is 4.18 J/g⋅K; specific heat capacity of water vapor is 1.84 J/g⋅K; heat of vaporization of water is 2.260 kJ/g).

(1) 16.2 kJ (2) 25.6 kJ (3) 5.4 kJ (4) 33.2 kJ (5) 1.6 kJ

I know that the answer is (2) 25.6 KJ but I do not know how to get to that answer. Thanks for your help!

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Homework Answers

Answer #1

Ti = 50.0 oC

Tf = 150.0 oC

here

Cl = 4.18 J/g.oC

Heat required to convert liquid from 50.0 oC to 100.0 oC

Q1 = m*Cl*(Tf-Ti)

= 10 g * 4.18 J/g.oC *(100-50) oC

= 2090 J

Lv = 2.26KJ/g =

2260J/g

Heat required to convert liquid to gas at 100.0 oC

Q2 = m*Lv

= 10.0g *2260.0 J/g

= 22600 J

Cg = 1.84 J/g.oC

Heat required to convert vapour from 100.0 oC to 150.0 oC

Q3 = m*Cg*(Tf-Ti)

= 10 g * 1.84 J/g.oC *(150-100) oC

= 920 J

Total heat required = Q1 + Q2 + Q3

= 2090 J + 22600 J + 920 J

= 25610 J

= 25.6 KJ

Answer: (2)

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