Question

1- The amount of energy needed to vapourize 786 g of water at its boiling point is ____________. ∆Hvap = 2.26 kJ/g

                a.            11,500 kJ

                b.            1,780 kJ

                c.             348 kJ

                d.            2.85x10-3 kJ

2- How much energy is necessary to transform 435.5 g of ice at -8.63°C to steam at 114.8°C? Cs ice = 2.09 J/g°C, ∆Hfus of H2Oice = 0.334 kJ/g, Cs water = 4.184 J/g°C, ∆Hvap of H2O = 2.26 kJ/g, Cs steam = 2.03 J/g°C

                a.            1,330 kJ

                b.            684 kJ

                c.             1,582 kJ

                d.            1,205 kJ

3- How much ice at 0˚C can be completely transformed to water 0˚C with 632 kJ of energy? ∆Hfus of H2Oice = 0.334 kJ/g

                a.            1,890 g

                b.            none

                c.             211 g

                d.            5.28x10-4 g

Answer 1